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JEE Advance - Physics (2013 - Paper 1 Offline - No. 19)

The work functions of silver and sodium are 4.6 and 2.3 eV, respectively. The ratio of the slope of the stopping potential versus frequency plot for silver to that of sodium is ___________.
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Explicaţie

We have,

$$V = {{hf} \over e} - {\phi \over e}$$

Slope is h/e.

JEE Advanced 2013 Paper 1 Offline Physics - Dual Nature of Radiation Question 13 English Explanation

Slope is the same for both silver and sodium.

Therefore, the ratio of the slope of the stopping potential versus frequency plot for silver to that of sodium is 1 : 1.

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